The function test for the blog Veröffentlicht am 2017-01-02 | Edited on 2019-04-05 Never quit forever。 2019.2.13又搞了一遍,测试下数学功能 $gi = \frac{i}{n}g_i + \frac {n-i}{n}g{i+1}+1$ $gi = g{i+1} + \frac{n}{n-i}$ $fi = \frac{i}{n}(f_i+g_i+1) + \frac{n-i}{n}(f{i+1}+g_{i+1}+1)$ · Go to download